3n=(3^2)^8

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Solution for 3n=(3^2)^8 equation: 



3n=(3^2)^8

We move all terms to the left:

3n-((3^2)^8)=0

determiningTheFunctionDomain
3n-3^2^8=0

We add all the numbers together, and all the variables

3n+122-1.3900845237714E=0

We add all the numbers together, and all the variables

3n+118.22135849901=0

We move all terms containing n to the left, all other terms to the right

3n=-118.22135849901

n=-118.22135849901/3

n=-39+1/2.456281265846

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